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If A has order P_1\times P_2 , B has order P_3\times P_4, C has order P_5\times P_6. Also,AC,BA and CB exist then which is WRONG?

  • Option 1)

    P_5=P_2

  • Option 2)

    P_1=P_4

  • Option 3)

    P_4=P_5

  • Option 4)

    P_3=P_6

 

Answers (1)

best_answer

As we learnt

 

Conformable matrices for multiplication -

A_{m\times n} \times B_{n\times p}

- wherein

Number of columns of first matrix is equal to number of rows in second matrix

 

 AC exists , so  P_2=P_5

BA exists, so  P_4=P_1

CB exists,so  P_6=P_3

 


Option 1)

P_5=P_2

Option 2)

P_1=P_4

Option 3)

P_4=P_5

Option 4)

P_3=P_6

Posted by

Himanshu

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