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A charge of + 4C is kept at a distance of 50 cm from a charge of – 6C. Find the two points where the potential is zero

  • Option 1)

    Internal point lies at a distance of 20 cm from 4C charge and external point lies at a distance of 100 cm from 4C charge.
     

  • Option 2)

    Internal point lies at a distance of 30 cm from 4C charge and external point lies at a distance of 100 cm from 4C charge 
     

  • Option 3)

    Potential is zero only at 20 cm from 4C charge between the two charges

  • Option 4)

    Potential is zero only at 20 cm from – 6C charge between the two charges 

Answers (2)

best_answer

As we learned 

 

Zero potential due to a system of two point charge - - wherein

For external point

\\*At\: P,\frac{Q_{1}}{x_{1}}= \frac{Q_{2}}{\left ( x+x_{1} \right )}\\* \Rightarrow x_{1}= \frac{x}{\left ( Q_{2}/Q_{1}-1 \right )}          

 

 For internal point X, X_{1}=\frac{X}{\left ( \frac{Q_{2}}{Q_{1}} +1\right )}=\frac{50}{\frac{6}{4}+1}=20cm

and for external point Y,

X_{1}=\frac{X}{\left ( \frac{Q_{2}}{Q_{1}} -1\right )}=\frac{50}{\frac{6}{4}-1}=100cm

 


Option 1)

Internal point lies at a distance of 20 cm from 4C charge and external point lies at a distance of 100 cm from 4C charge.
 

Option 2)

Internal point lies at a distance of 30 cm from 4C charge and external point lies at a distance of 100 cm from 4C charge 
 

Option 3)

Potential is zero only at 20 cm from 4C charge between the two charges

Option 4)

Potential is zero only at 20 cm from – 6C charge between the two charges 

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