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  • Solve this problem Find the electric field due to an long cylinder of radius 5 cm having linear charge density 3.5 X 10-2 C/m at a distance of 5 cm from cylinder .

Find the electric field due to an long cylinder of radius 5 cm having linear charge density 3.5 X 10-2 C/m at a distance of 5 cm from cylinder .

  • Option 1)

    0

  • Option 2)

    12.6 x 109

  • Option 3)

    1.2 X 102

  • Option 4)

    126

 

Answers (1)

best_answer

As we learnt ,

 

If r = R for both cylinder -

E_{surface}=\frac{\lambda }{2\lambda \varepsilon _{0}R}

V_{surface}=\frac{-\lambda }{2\lambda \varepsilon _{0}}\log_{e}R+c

 

- wherein

\lambda - Linear charge density.

 

 as r = R

E = \frac{\lambda}{2\pi\epsilon _ {o}r } \; \Rightarrow \; E = \frac{\lambda}{2\pi\epsilon _ {o}r } \times \frac{2}{2}

 

E =\frac{2\lambda K}{R} = \frac{2 \times 3.5 \times 10 ^{-2} \times 9 \times 10^{9}}{5 \times 10 ^{-2}}

 


Option 1)

0

Option 2)

12.6 x 109

Option 3)

1.2 X 102

Option 4)

126

Posted by

Aadil

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