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One mole of diatomic ideal gas undergoes a cyclic process ABC as shown in figure. The process BC is adiabatic. The temperatures at A, B and C are 400 K, 800 K and 600 K respectively. Choose the correct statement :

 

  • Option 1)

    The change in internal energy in whole cyclic process is 250 R.
     

     

  • Option 2)

    The change in internal energy in the process CA is 700 R. 

  • Option 3)

    The change in internal energy in the process AB is - 350 R.

     

  • Option 4)

    The change in internal energy in the process BC is - 500 R.

 

Answers (1)

best_answer

As we have learned

First law in isobaric process -

\Delta U= n\, C_{v}\Delta T

= n\frac{R}{\gamma -1}\Delta T
 

- wherein

\Delta Q= \Delta U+W

         = n\frac{\gamma \: R}{\gamma -1}\cdot \Delta T

\Delta Q= nC_{p}\: \Delta T

 

 

change in interval energy in cyclic process = 0 

For CA \Delta V = \frac{f}{2 } R\Delta T = 5/ 2 \times R \times -200= -500R

For AB  \Delta V = 5/ 2 \times R \times400 =1000R

For BC \Delta V = 5/ 2 \times R \times(-200 ) =-500 R

 

 

 


Option 1)

The change in internal energy in whole cyclic process is 250 R.
 

 

Option 2)

The change in internal energy in the process CA is 700 R. 

Option 3)

The change in internal energy in the process AB is - 350 R.

 

Option 4)

The change in internal energy in the process BC is - 500 R.

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Avinash

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