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for real numbers x and y; we write as xRy\Rightarrow x-y+\sqrt{2} is an irrational number. Then relation R is

  • Option 1)

    Reflexive

  • Option 2)

    Symmetric

  • Option 3)

    Transitive

  • Option 4)

    none of these

 

Answers (1)

best_answer

As we learnt

 

TRANSITIVE RELATION -

 

A relation R in A is said to be transitive, if a R b and b R c ⇒ a R c ∀ a,b,c ∈ A

-

 

 for any x\inR; we have x-x+\sqrt{}2\Rightarrow irrational number

But R is neither symmetric nor transitive.

 


Option 1)

Reflexive

Option 2)

Symmetric

Option 3)

Transitive

Option 4)

none of these

Posted by

Himanshu

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