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 Van der Waal’s equation for a gas is stated as,

p= \frac{nRT}{V-nb}-a\left ( \frac{n}{V} \right )^{2}.

This equation reduces to the perfect gas eqution ,

p= \frac{nRT}{V}when.

  • Option 1)

     temperature is sufficiently high and pressure is low.
     

     

  • Option 2)

     temperature is sufficiently low and pressure is high.

  • Option 3)

     both temperature and pressure are very high.

     

  • Option 4)

    both temperature and pressure are very low.

 

Answers (1)

best_answer

As we have learned

Vander waal equation for real gas -

\left (p+\frac{an^{2}}{v} \right )(V-nb)=nRT

- wherein

a, b : Vander waal Constants, P- Pressure, V- Volume, n- No. of moles, R- Gas Constant, T- Temperature

 

 At high temprarture and low pressure real gas behaves as ideal gas 

 


Option 1)

 temperature is sufficiently high and pressure is low.
 

 

Option 2)

 temperature is sufficiently low and pressure is high.

Option 3)

 both temperature and pressure are very high.

 

Option 4)

both temperature and pressure are very low.

Posted by

SudhirSol

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