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  • Solve! Two bodies of masses 1 kg and 4 kg are connected to a vertical spring, as shown in the figure. The smaller mass executes simple harmonic motion of angular frequency 25 rad/s, and amplitude 1.6 cm while the bigger mass remains stationary on the

Two bodies of masses 1 kg and 4 kg are  connected to a vertical spring, as shown in the figure. The smaller mass executes simple harmonic motion of angular frequency 25 rad/s, and amplitude 1.6 cm while the bigger mass remains stationary on the ground. The maximum force exerted by the system on the floor is (take g = 10 ms-2).

  • Option 1)

    20 N

  • Option 2)

    10 N

  • Option 3)

    60 N

  • Option 4)

    40 N

 

Answers (1)

best_answer

As we learned 

 

Time period of oscillation for spring mass system -

T= 2\pi \sqrt{\frac{m}{K}}

- wherein

m = mass of block

K = spring constant

 

 T=2\pi \sqrt{\frac{m}{k}}

or\; \frac{2\pi }{w}\; 2\pi \sqrt{\frac{m}{k}}\; or\; \frac{1}{25}=\sqrt{\frac{1}{k}}

m=1kg\; ,\; w=25rad/s

or k=625Nm^{-1}

maximum force F=Mg+kx+mg

=4\times 10+625\times 1.6\times 10^{-2}+1\times 10

=60N

 

 


Option 1)

20 N

Option 2)

10 N

Option 3)

60 N

Option 4)

40 N

Posted by

Aadil

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