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The focal length of the objective and the eyepiece of compound microscope are 2cm and 3cm respectively. The distance between the objective and eyepiece is 15 cm. The final image formed by eyepiece is at infinity the distance (in cm) of the object and image produced by the objective, measured from the objective lens are respectively.

Option: 1

2.4 and 12


Option: 2

2.4 and 15


Option: 3

2.3 and 3


Option: 4

2.3 and 12


Answers (1)

As we learnt

Length of compound microscope -

L= v_{o}+u_{e}
 

v_{o}= Image distance from objective.

u_{e}= Object distance from eyepiece

 

 f_{0} = 2 cm    f_{e} = 3cm

l = 15cm

Final image formed at infinity hence image formed by objective is at focal point of eyepiece

u_{e}=f_{e}=3cm

v_{o}= l-f_{e}=12cm

For objective:

v_{o}=12cm                        f_{o}=2cm

\frac{1}{v_{0}}-\frac{1}{u_{0}}=\frac{1}{f_{0}}

\frac{1}{12}-\frac{1}{u_{0}}=\frac{1}{2}                    

or

\frac{1}{u_{0}}=\frac{1}{12}-\frac{1}{2}=\frac{1-6}{12}

or,

 u_{0}=-2.4cm                v_{0}=12cm

Posted by

Sumit Saini

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