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If the satellite whose mass m is revolving in circular orbit of radius r around the earth (mass of earth =M). The time of revolution of satellite is:

Option: 1

T\alpha {\frac{r^{3}}{\sqrt{GM}}}


Option: 2

T\propto \frac{r^{\frac{3}{2}}}{\sqrt{GM}}


Option: 3

T\alpha \frac{{\sqrt{GM}}}{r3}


Option: 4

T\alpha \frac{{\sqrt{GM}}}{r^{\frac{3}{2}}}


Answers (1)

best_answer

As we learn

 T = \frac{2\pi r}{v_{0}} = \frac{2\pi r}{\sqrt{\frac{GM}{r}}}

T = \frac{2\pi r}{\sqrt{\frac{GM}{r}}}^{\frac{3}{2}}

T \propto \frac{r^{\frac{3}{2}}}{\sqrt{GM}}

 

Posted by

rishi.raj

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