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In young's double slit experiment, D=1m, d=1mm and \lambda =\frac{1}{2}mm then highest order of maxima is:

Option: 1

1


Option: 2

2


Option: 3

3


Option: 4

4


Answers (1)

best_answer

As we learn

Maximum order of interference maxima -

n_{max}= {\left [ \frac{d}{\lambda} \right ]}

 

- wherein

Where  \left [\, \, \, \right ] represent the greatest integer

 

 

Highest order maxima 

n_{max}= {\left [ \frac{d}{\lambda} \right ]}={\left [ \frac{1}{ \frac{1}{2}} \right ]}=2

 

Posted by

seema garhwal

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