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The total energy of an electron in the first excited state of hydrogen is about -3.4eV. Its kinetic energy (in eV) in this state is:

Option: 1

3.4


Option: 2

-6.8


Option: 3

6.5


Option: 4

-3.4


Answers (1)

As we learn

Relation between K.E., P.E. & Total energy -

K.E.=- \left ( Total\: energy \right )=-\frac{1}{2}\left ( Potential \: energy \right )

- wherein

Potential Energy and total energy are negative .While kinetic energy is positive

 Total KE  = - (Total energy of electron in that orbit )

                 = - (-3.4eV) = 3.4eV   

Posted by

Ramraj Saini

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