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Electric field strength that balance gravitational force on an electron is

 

Option: 1

5.7*10-10 v/m

 


Option: 2

5.7*10-11 v/m

 


Option: 3

4.7*10-10 v/m

 


Option: 4

4.7*10-11 v/m


Answers (1)

best_answer

As we learn

Millikan's oil drop method -

Milikan measured the charge on an electron by this oil drop method. 

- wherein

We adjust the voltage in the plates so that the electrical attraction upward just balances the force of gravity downward.

 

 

At equilibrium

eE = mg

E = \frac{mg}{e} = \frac{9.1*10^{-31}*10}{1.6*10^{-19}} = 5.7*10^{-11}v/m

 

Posted by

HARSH KANKARIA

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