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Distance of closet approach of \alpha particle is proportional to

Option: 1

\frac{1}{K.E}


Option: 2

K.E


Option: 3

\frac{1}{Z}


Option: 4

None of the above


Answers (1)

best_answer

As we learn

Defect of Rutherford model -

1. Position of the electron was not mentioned.

2. Stability of the atom was not explained.

3. Line spectrum cannot be explained.

 

From energy conservation 

K.E = \frac{1}{4\pi \epsilon _{0}}\cdot \frac{\left ( ze \right )\left ( 2e \right )}{b}

b = distance of closest approach

b = \frac{2ze^{2}}{4\pi \epsilon _{0}(K.E)}

b \propto \frac{1}{K.E}

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