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A 10 mg effervescent tablet containing sodium  bicarbonate and oxalic acid releases 0.25 ml of CO_{2} at T = 298.15 K and p = 1 bar . If molar volume of   CO_{2}  is 25.0 L under such condition , what is the percentage of sodium bicarbonate in each tablet ?

[Molar mass of NaHCO3 = 84 g mol-1]

  • Option 1)

    0.84

  • Option 2)

    8.4

  • Option 3)

    16.8

  • Option 4)

    33.6

Answers (1)

best_answer

 

Molarity -

 Molarity (M) = (Number of moles of solute)/(volume of solution in litres)

 

- wherein

It is defined as the number of moles of the solute in 1 litre of the solution.

As we know that

Reaction 2NaHCO_{3}+H_{2}C_{2}O_{4}\rightarrow Na_{2}C_{2}O_{4}+2CO_{2}+2H_{2}O

n=\frac{0.25}{25000}=10^{-5},W=84\times 10^{-5}g;\,=\frac{84\times 10^{-5}}{10^{-2}}100=8.4%

ans\, \, is\, \, 8.4%%

 


Option 1)

0.84

Option 2)

8.4

Option 3)

16.8

Option 4)

33.6

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