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  • Stuck here, help me understand: . An electron of massmand charge e is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be

.  An electron of massm  and charge e  is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be

  • Option 1)

    V\sqrt{e/m}

  • Option 2)

    \sqrt{eV/m}

  • Option 3)

    \sqrt{2eV/m}

  • Option 4)

    2eV/m

 

Answers (1)

As we have learned

when Charged Particle at rest in uniform field -

W=Q\cdot \Delta v

-

 

 Kinetic energy K=1/2mv^2 =    ev \Rightarrow v= \sqrt{2eV/m}


Option 1)

V\sqrt{e/m}

Option 2)

\sqrt{eV/m}

Option 3)

\sqrt{2eV/m}

Option 4)

2eV/m

Posted by

Vakul

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