If n(AxB) = 40 and n(A) = 4, then find n(B).
5
10
8
6
Aswe have learnt,
No. of elements in cartesian product -
If A and b are finite sets, then n(AXB)=n(A).n(B)
-
40 = n(A) x n(B)
n(B) = 40/4 = 10
Option 1)
5
Option 2)
10
Option 3)
8
Option 4)
6
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