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  • Stuck here, help me understand: - Redox Reaction and Electrochemistry - JEE Main-3

Calculate thee emf of the following concentration cell at 25 \degree

Ag(s)|AgNO_3(0.01M) || AgNO_3(0.05 M) |Ag(s)

  • Option 1)

    -0.414V 

  • Option 2)

    0.828V 

  • Option 3)

    0.414 V

  • Option 4)

    .00414V 

 

Answers (1)

best_answer

As we have learned

Concentration Cells -

A cell in which electrical energy is produced by the transference of a substance from a system of high concentration to one at low at low concentration is known as concentration cells.

-

 

 E=E^0 - \frac{0.0591}{n} log _{10}Q

= 0- \frac{0.0591}{1} Log_{10}\left ( \frac{0.01}{0.05} \right )= 0.0414 V

 


Option 1)

-0.414V 

Option 2)

0.828V 

Option 3)

0.414 V

Option 4)

.00414V 

Posted by

satyajeet

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