The molar conductivities of KCl, NaCl and KNO3 are 152, 128 and 111 S cm2 mol-1 repectively. What is the molar conductivity of NaNO3 ?

  • Option 1)

    101 S cm2 mol-1 

  • Option 2)

    87 S cm2 mol-1 

  • Option 3)

    -101 S cm2 mol-1 

  • Option 4)

    -391 S cm2 mol-1 

 

Answers (1)
P Plabita

As we have learnt,

 

Formula for limiting molar conductivity for electrolyte -

\Lambda_{m}^{0}= \lambda _{+}^{0}.\nu _{+}\:+\:\nu _{-}.\lambda_{-}^{0}

\lambda _{+}^{0}\:and\:\lambda_{-}^{0}

are limiting molar conductivities of cation and anion respectively.

- wherein

if an electrolyte on dissociation gives \nu_{+} \:cation\:and\: \nu_{-} anions.

 

 \Lambda^o_{NaNO_3} = \Lambda^{0}_{NaCl} + \Lambda^{0}_{KNO_3} -\Lambda^{0}_{KCl} = 128 + 111 - 152 = 87

 


Option 1)

101 S cm2 mol-1 

Option 2)

87 S cm2 mol-1 

Option 3)

-101 S cm2 mol-1 

Option 4)

-391 S cm2 mol-1 

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