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Stuck here, help me understand: - The perpendicular distance from the origin to the plane containing the two lines, and is : - Three Dimensional Geometry - JEE Main

The perpendicular distance from the origin to the plane containing the two lines, \frac{x+2}{3}=\frac{y-2}{5}=\frac{z+5}{7}  and  \frac{x-1}{1}=\frac{y-4}{4}=\frac{z+4}{7}  is : 

  • Option 1)

    \frac{11}{\sqrt{6}}

     

     

  • Option 2)

    6\sqrt{11}

  • Option 3)

    11

  • Option 4)

    11\sqrt{6}

Answers (1)
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A admin

 

Condition for line to be lie in plane -

\vec{b}\cdot \vec{n}= 0 and \vec{a}\cdot \vec{n}= d or

a_{1}a+b_{1}b+c_{1}c= 0  and a_{1}x_{1}+b_{1}y_{1}+c_{1}z_{1}+d= 0

-

 

 


Option 1)

\frac{11}{\sqrt{6}}

 

 

Option 2)

6\sqrt{11}

Option 3)

11

Option 4)

11\sqrt{6}

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