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  • Stuck here, help me understand: Two point charges Q and – 3Q are placed at some distance apart. If the electric field at the location of Q is E, then at the locality of – 3Q, it is

Two point charges Q and – 3Q are placed at some distance apart. If the electric field at the location of Q is E, then at the locality of – 3Q, it is

  • Option 1)

    -E

  • Option 2)

    E/3

  • Option 3)

    -3E

  • Option 4)

    -E/3

 

Answers (1)

 

As we learned

 

Electric field and potential Due to various charge Distribution i) Point Charge -

Electric field and Potential at Point P due to a Point charge Q.

E= \frac{kQ}{r^{2}}    ,     V= \frac{kQ}{r}

- wherein

 

  

Let the charge Q and – 3Q be placed respectively at A and B at a distance x Now we will determine the magnitude and direction to the field produced by charge – 3Q at A, this is E as mentioned in the Example.

\therefore E=\frac{3Q}{x^{2}}  (along AB directed towards negative charge)

Now field at location of – 3Q i.e. field at B due to charge Q will be  

{E}'=\frac{Q}{x^{2}}=\frac{E}{3}

(along AB directed towards negative charge)

 


Option 1)

-E

Option 2)

E/3

Option 3)

-3E

Option 4)

-E/3

Posted by

Vakul

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