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Which of the following is correct

  • Option 1)

    for  charged non-conducting sphere   V_{centre}>V_{surface}>V_{out}

     

     

     

  • Option 2)

    for  charged non-conducting sphere   V_{centre}\leq V_{surface}>V_{out}

  • Option 3)

    for  charged non-conducting sphere       V_{centre}> V_{surface}= V_{out}

  • Option 4)

    for  charged non-conducting sphere       V_{centre}> V_{surface}\equiv V_{out}    

 

Answers (1)

best_answer

As we learned

 

Potential - If P lies at centre of uniformly charged non-conducting sphere -

V_{centre}=\frac{3}{2}\times \frac{1}{4\pi \epsilon _{0}}\frac{Q}{R}=\frac{3}{2}V_{s}

i.e         \dpi{100} V_{c}> V_{s}

-

 

 V_{centre}=\frac{3}{2}\times \frac{1}{4\pi \varepsilon _{0}}\cdot \frac{Q}{R}=\frac{3}{2}V_{s}


Option 1)

for  charged non-conducting sphere   V_{centre}>V_{surface}>V_{out}

 

 

 

Option 2)

for  charged non-conducting sphere   V_{centre}\leq V_{surface}>V_{out}

Option 3)

for  charged non-conducting sphere       V_{centre}> V_{surface}= V_{out}

Option 4)

for  charged non-conducting sphere       V_{centre}> V_{surface}\equiv V_{out}    

Posted by

Avinash

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