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  • Tell me? A non ideal solution was prepared by mixing 30 ml chloroform and 50 ml acetone. The volume of mixture will be

A non ideal solution was prepared by mixing 30 ml chloroform and 50 ml acetone. The volume of mixture will be

  • Option 1)

    > 80 ml

  • Option 2)

    < 80 ml

  • Option 3)

    = 80 ml

  • Option 4)

    \geq 80 ml

 

Answers (1)

best_answer

As we learned

 

Condition for negative deviation -

When A - A interactions and B - B  interactions  are  weaker than A - B interactions.

e.g. Acetone + Chloroform

- wherein

\Delta H_{mix}< 0

\Delta V_{mix}< 0

(V_{f}< V_{A}+V_{B} )

\Delta H - Change\: in\: enthalpy

\Delta V - Change\: in\: volume

 

 

Chloroform & acetone form a non-ideal solution, in which A.....B type interaction are more than A...... A & B......B type interaction due to
H -bonding. Hence, the solution shows, negative deviation from Raoult’s Law i.e.,

\Delta V_{mix}=-ve;                            \Delta H_{mix}=-ve;

\therefore  total volume of solution = less than (30 + 50 ml)

    or < 80ml

 


Option 1)

> 80 ml

Option 2)

< 80 ml

Option 3)

= 80 ml

Option 4)

\geq 80 ml

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Plabita

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