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  • Tell me? - A series AC circuit containing an inductor (20mH), a capacitor (120) and a resistor (60) is driven b - Electromagnetic Induction and Alternating currents - JEE Main

A series AC circuit containing an inductor (20mH), a capacitor (120\mu F) and a resistor (60\Omega) is driven by an AC source of \frac{24V}{50Hz}. The energy dissipated in the circuit in 60s is:

 

  • Option 1)

    2.26 \times 10^{3}J

  • Option 2)

    5.17 \times 10^{2}J

  • Option 3)

     

    3.39 \times 10^{3}J

  • Option 4)

     

    5.65 \times 10^{2}J

Answers (1)

best_answer

 

RLC circuit Voltage -

V_{R}=iR\: \: \: V_{L}= {i}\ X_{L}\: \: \: V_{C}={i}\ X_{C}

- wherein

Power Dissipated = I^{2}R

Energy = I^{2}Rt

I=\frac{V}{\sqrt{R^{2}+(\omega L-\frac{1}{\omega L})^{2}}}

  L= 20mH\: ,\: C=120\mu F\: , \omega =2\pi\times 50 \: ,\: V=24

Substituiting values 

Energy = 5.18\times 10^{2}J

           = 5.17\times 10^{2}J

 

 


Option 1)

2.26 \times 10^{3}J

Option 2)

5.17 \times 10^{2}J

Option 3)

 

3.39 \times 10^{3}J

Option 4)

 

5.65 \times 10^{2}J

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