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The crystal field splitting energy for octahedral complex (\Delta _{0}) and that for tetrahedral complex (\Delta _{t}) are related as 

  • Option 1)

    \Delta _{t}=4/9\Delta _0

  • Option 2)

    \Delta _{t}=0.5\Delta _0

  • Option 3)

    \Delta _{t}=0.33\Delta _0

  • Option 4)

    \Delta _{t}=9/4\Delta _0

 

Answers (1)

best_answer

As we have learned

Comparison in delta o and delta t -

\bigtriangleup t = \frac{4}{9}\bigtriangleup \circ

-

 

 

(A) This may attributes to the following two reasons.

         (i) There are only four ligands instead of six, so the ligand field is only two thirds the size ; as the ligand field splitting is also the two thirds the size and (ii) the direction of the orbitals does not concide with the direction of  the ligands. This reduces the crystal field splitting by roughly further two third. So \Delta _t = 2/3*2/3=4/9\Delta _0

 


Option 1)

\Delta _{t}=4/9\Delta _0

Option 2)

\Delta _{t}=0.5\Delta _0

Option 3)

\Delta _{t}=0.33\Delta _0

Option 4)

\Delta _{t}=9/4\Delta _0

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Aadil

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