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A particle of mass 2g and charge 1\mu C is held at a distance of 1 metre from a fixed charge of 1\mu C.  If the particle is released it will be repelled. The speed of the particle when it is at a distance of 10 metres from the fixed charge is

  • Option 1)

    100 m/s

  • Option 2)

    90 m/s

  • Option 3)

    60 m/s

  • Option 4)

    45 m/s

 

Answers (1)

As we have learnt, 

 

when Charged Particle at rest in uniform field -

Velocity - 

\dpi{100} v=\frac{QEt}{m}=\sqrt{\frac{2Q\Delta V}{m}}

 

 

- wherein

\Delta V= Potential difference.

 

 

According to conservation of energy

Energy of moving charge at A = Energy of moving charge at B

9\times 10^9 \times \frac{10^{-3}\times 10^{-6}}{10} + \frac{1}{2}\times 2\times 10^{-3} V^2\Rightarrow v^2 = 8100\Rightarrow v = 90 m/s


Option 1)

100 m/s

Option 2)

90 m/s

Option 3)

60 m/s

Option 4)

45 m/s

Posted by

Vakul

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