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  • Tell me? - Redox Reaction and Electrochemistry - JEE Main

If C = 0.000521 mol L^{-1}and \Lambda_m = 147.81 Scm^2mol^{-1}, then what would be the value of \Lambda^o_m if A = 87.46 \frac{S cm^2 mol^{-1}}{(mol L^{-1})^\frac{1}{2}}

  • Option 1)

    147.856

  • Option 2)

    147.854

  • Option 3)

    147.888

  • Option 4)

    147.899

 

Answers (1)

best_answer

As we have learnt,

 

Variation of Molar Conductivity in strong electrolyte -

\Lambda m=\Lambda^{0} m-AC^{\frac{1}{2}}

- wherein

For strong electrolyte, \Lambda m increases slowly with dilution.

 

 \Lambda_m = \Lambda_m^o - AC^{\frac{1}{2}} \\*\Rightarrow \Lambda^o_m = \Lambda_m + AC^{\frac{1}{2}} = 147.81 + 87.46\times 0.000521 = 147.8555 \approx 147.856

 


Option 1)

147.856

Option 2)

147.854

Option 3)

147.888

Option 4)

147.899

Posted by

prateek

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