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  • Tell me? The velocity of water in a river is 18 km/hr near the surface. If the river is 5 m deep , find the shearing stress between the horizontal layers of water.The co-efficient of viscosity of water=10-2 poise.

The velocity of water in a river is 18 km/hr near the surface. If the river is 5 m deep , find the shearing stress between the horizontal layers of water.

The co-efficient of viscosity of water=10-2 poise.

 

  • Option 1)

    10^{-1}\: N/m^{2}

  • Option 2)

    10^{-2}\: N/m^{2}

  • Option 3)

    10^{-3}\: N/m^{2}

  • Option 4)

    10^{-4}\: N/m^{2}

 

Answers (1)

best_answer

As we have learned @1172

viscous\ force = -\eta A\frac{dv}{dx}\\shearing stress =\frac{F}{A}=\eta \frac{dv}{dx}\\=10^{-2}\times\frac{18\times1000}{3600\times5}\\=10^{-2 }Nm^{-2}


Option 1)

10^{-1}\: N/m^{2}

Option 2)

10^{-2}\: N/m^{2}

Option 3)

10^{-3}\: N/m^{2}

Option 4)

10^{-4}\: N/m^{2}

Posted by

SudhirSol

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