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The acceleration of a particle is increasing linearly with time t as bt. The particle starts from the origin with an initial velocity v_0

The distance travelled by the particle in time t will be ?

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@ Ravindra

Given the acceleration  as a function of time:

a(t)=bt

Integrate to obtain the velocity as a function of time.v(t)={\frac{1}{2}}bt^2+C 

 We are told that the constant of integration is V0

v(t)={\frac{1}{2}}bt^2+V_{0}

Integrate, again, to obtain the displacement as a function of time.d(t)=16bt^3+V_{0}t+c

The phrase "starts from the origin" tells us that the integration constant is 0:

d(t)=16bt^3+V_{0}t

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avinash.dongre

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