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The H-P-H angle inP\! H_{3} is smaller than that H-\! N\! -H angle in N\! H_{3} because:

Option: 1

Higher electronegativity of nitrogen.


Option: 2

More repulsion between lone pair and bond pair in N\! H_{3} .


Option: 3

Lower electronegativity of nitrogen


Option: 4

None


Answers (1)

Bond Parameters: length, angle, energy, strength -

Bond angle

It is the angle between any two covalent bonds that share a common atom as shown in figure.

 

 

A pair of images are shown. The left image shows a carbon atom with three atoms bonded in a triangular arrangement around it. There are two hydrogen atoms bonded on the left side of the carbon and the angle between them is labeled, “118 degrees” and, “Bond angle.” The carbon is also double bonded to an oxygen atom. The double bond is shaded and there is a bracket which labels the bond, “Bond length ( angstrom ), ( center to center ),” and, “1.21 angstrom.” The right image shows a ball-and-stick model of the same elements. The hydrogen atoms are white, the carbon atom is black, and the oxygen atom is red.

Bond distances (lengths) and angles are shown for the formaldehyde molecule, H2CO.

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As we have learnt ,

Solution: As we have learnt ,
Repulsion is less between lone pair and the bond pair in N\! H_{3} due to high electronegativity of nitrogen which holds the electron very tightly towards the nucleus. This results in less movement of electron pair on nitrogen atom and therefore H-\! N\! -H angle in N\! H_{3} is greater than H-\! P\! -H angle in P\! H_{3}.
Hence, option number (1) is correct.

Posted by

Ramraj Saini

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