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The angular velocity of a motorcycle tire of diameter 10 inches rotates 5 times a second is:

 

Option: 1

6 \pi


Option: 2

10 \pi


Option: 3

12\pi


Option: 4

20 \pi


Answers (1)

best_answer

 Time period-

  • Time taken to complete one rotation

  • Formula-

                           T=\frac{2\pi }{\omega }

                            Where    

            If N= no.of revolutions and t=total time then

                           T=\frac{t }{N } or    (\omega =\frac{2\pi N}{t})

  • S.I unit seconds (s)

   

As \omega = 2\pi f.So\: \: \omega = 2\pi \times 5= 10\pi \: rad/sec

Posted by

Pankaj

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