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The atomic number of four elementsP,Q,R,S are6,8,10 and 12 respectively.
The two elements which can react to form ionic compounds are:

Option: 1

P\: and\: S


Option: 2

Q\: and \: R


Option: 3

P\: and \: R


Option: 4

Q\: and \: S


Answers (1)

best_answer

Q atom’s electronic configuration is \mathrm{2,6} and S atom is \mathrm{2,8,2}. Therefore S has 2 electrons in its outer most shell, so it will lose 2 electrons to Q and both will attain inert gas configuration.
Hence, option number (4) is correct

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Gunjita

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