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The coefficent of friction between tyers and road is 0.5. The maximum speed (in m/s) with which a car be driven round a curve a radius of 20m without skidding is [ g = 10m/s2]

Option: 1

10


Option: 2

40


Option: 3

15


Option: 4

20


Answers (1)

best_answer

 

 

Skidding of Vehicle on a Level Road -

Frictional force \geq Req. centripetal Force

\mu mg \geq \frac{mv^{2}}{r}

V_{safe}\leq \sqrt{\mu rg}

V_{safe}=Safe vector move

r = radius of the curve

\mu= coefficient of friction

  • V_{safe} is the maximum velocity by which vehicle can turn on a circular path of radius r. 

 

So,

\mu mg =\frac{mv^{2}_{max}}{r}

v_{max} = \sqrt{\mu rg} = \sqrt{0.5 \times 20\times 10} = 10m/s

 

Posted by

Deependra Verma

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