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  • The coordination number and the oxidation state of the element in the complex  <img al

The coordination number and the oxidation state of the element \mathrm{E} in the complex  \mathrm{\left[E(e n)_{2}\left(C_{2} O_{4}\right)\right] N O_{2}}  are respectively

(Where (en)  is ethylene diamine)

Option: 1

6 and 3


Option: 2

6 and 2


Option: 3

4 and 2


Option: 4

4 and 3


Answers (1)

best_answer

In the complex \mathrm{\left [ E(en)_2C_2O_4 \right ]NO_2},

Coordination number of E is 6 since it is coordinated with two ethylene diamine ligands and one Oxalate ligand, both of which are bidentate. 

The oxidation state of element E is +3.

Therefore, option (1) is correct.

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