The correct order of spin-only magnetic
moments among the following is :
(Atomic number : Mn=25, Co=27,
Ni=28, Zn=30)
(1) [ZnCl4]2− > [NiCl4]2− > [CoCl4]2−
> [MnCl4]2−
(2) [CoCl4]2− > [MnCl4]2− > [NiCl4]2−
> [ZnCl4]2−
(3) [NiCl4]2− > [CoCl4]2− > [MnCl4]2−
> [ZnCl4]2−
(4) [MnCl4]2− > [CoCl4]2− > [NiCl4]2−
> [ZnCl4]2−
have no unshared electron
have two free electrons
have three free electrons
have five free electrons
So,
The order of the spin magnetic moment will be
Hence option D is correct.
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