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  • The diameter of the objective lens of microscope makes an angle at the focus  of the microscope. F

The diameter of the objective lens of microscope makes an angle \beta at the focus  of the microscope. Further, the medium between the object and the lens is an oil of refractive index n. Then the resolving power of the microscope.

 

Option: 1

 Increases with decreasing value of n
 


Option: 2

 Increases with decreasing value of  \beta


Option: 3

  Increases with increasing value of n\sin 2\beta

 


Option: 4

 Increases with increasing value of   \frac{1}{n\sin 2\beta }


Answers (1)

best_answer

 

As we had learnt in

Resolving power of microscope -

R= \frac{2\mu \sin \Theta }{\lambda }

\mu = Refractive\: index

\lambda = wavelength \: of \: light \: used

-

 

 

Resolving power of microscope 

R.P = \frac{2\mu \sin \theta }{\lambda }

\lambda = wavelength \\\mu = refractive \: \: index \\ \theta = angle

Increase with  increase \mu \sin \theta

Posted by

Nehul

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