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  • The electric potential is given by as a function of distance <img alt="x(m)" src="https://entrancecorner.oncodecogs.com/gif.la

The electric potential Vis given by as a function of distance x(m) by -
v=\left(5 x^{2}+10 x-9\right) \text { volt. value of electric field at x=1 is- }

Option: 1

20 \, \mathrm{v} / \mathrm{m}


Option: 2

6\, \mathrm{~v} / \mathrm{m}


Option: 3

11\, \mathrm{v} / \mathrm{m}


Option: 4

-20\, \mathrm{v} / \mathrm{m}


Answers (1)

best_answer

we know electric field is given by -

\vec{E}=-\frac{d v}{d x}=-\frac{d}{d x}\left[5 x^{2}+10 x-9\right]
\vec{E}=\left(-10 x^{2}-10\right)

Now,
Electric field at x=1 become-

(\vec{E})_{\text {at } k=1} =-10 - 10
                    =-20 \, \mathrm{~v} / \mathrm{m}  Ans.

Posted by

Devendra Khairwa

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