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The given network is a part of a bigger network. Determine the value of current flowing in resistor R_{6}.

Option: 1

9 A


Option: 2

8 A


Option: 3

7 A


Option: 4

1 A


Answers (1)

best_answer

The current I in R_6 can be calculated by applying Kirchhoff's current law. However, here it is not necessary to first find the currents through individual resistances, R_2$, $R_3, R_4 and R_5. Instead, we can treat the whole network inside the dotted box as a single junction. To this junction, currents I_1 and I_2 are entering and currents I_3 and I are leaving. Hence, according to K C L,

\begin{aligned} & I_1+I_2-I_3-I=0 \\ or\, \, \, \, \, \, & I=I_1+I_2-I_3 \\ & =3+5-1 \\ & =7 \mathrm{~A} \\ & \end{aligned}

Hence, answer (c) is correct.

Posted by

Divya Prakash Singh

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