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  • The half life of a second order process is  Option: 1 Independent of initial concentration<stron

The half life of a second order process is

 

Option: 1

Independent of initial concentration


Option: 2

Directly proportional to initial concentration 


Option: 3

Inversely proportional to initial concentration 


Option: 4

Inversely proportional to square of initial concentration


Answers (1)

best_answer

Half-time of a reaction \mathrm{t_{3 / 2}=[A o]^{1-n}}  where Ao  is initial concentration of reactant and \mathrm{n} is order of reaction with respect to that reactant.
For a second order reaction,\mathrm{ \mathrm{n}=2}

\mathrm{ \mathrm{t}_{3 / 2}=[\mathrm{Ao}]^{1-2}=1 /[\mathrm{Ao}] }
Hence, The half life of a second order process is inversely proportional to initial concentration.

Posted by

Divya Prakash Singh

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