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The lines x+2 y+3=0, x+2 y-7=0 and 2 x-y-4=0 are the sides of a square. Equation of the remaining side of the square can be -

Option: 1

2 x-y-14=0


Option: 2

2 x-y+8=0


Option: 3

2 x-y-10=0


Option: 4

2 x-y-6=0


Answers (1)

best_answer

Distance between x+2 y+3=0  and x+2 y-7=0 is \frac{10}{\sqrt{5}}  . Let the remaining side be 2 x-y+\lambda=0  We have, \frac{|\lambda+4|}{\sqrt{5}}=\frac{10}{\sqrt{5}} \Rightarrow \lambda=5,-14
thus remaining side is 2 x-y+6=0 \text { or } 2 x-y-14=0

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seema garhwal

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