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The minimum number of cells required to produce a current of 1.5A through a resistance of 30\Omega is [EMF of each cell is 1.5V and the internal resistance is 1\Omega

Option: 1

120


Option: 2

60


Option: 3

90


Option: 4

30


Answers (1)

best_answer

As we learnt

 

Mixed grouping -

 

if n identical cell's are connected in a row and such m row's are connected in parallel

- wherein

 

 Let no of cells in each row=n

and no. of rows =m

Then, 30=\frac{n*1}{m}\: \: or\: \: n=30m

1.5A= \frac{n*1.5}{30+\frac{n}{m}}\: \: or\: \: 30+\frac{n}{m}= n

30+30=n

\therefore n=60

\Rightarrow m=2

Minimum number of cells is mn=120

Posted by

HARSH KANKARIA

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