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Screenshot_691.png The molality of 90% H2So4 Solution is

Answers (1)

 

Relation between concentration terms (Molality & Molarity) -

\dpi{100} m=\frac{1000M}{1000d-Mm_{1}}

- wherein

m=Molality

M=Molarity

m_{1}=Molar\: mass\: of \: solute

\dpi{100} d=density\: of \: solution \: g/ml

 

 The density of solution = 1.8gm/ml
Weight of one litre of solution = 1800gm

 \therefore  Weight of H_{2}SO_{4} in the solution = =\frac{1800\times 90}{100}= 162gm

\therefore Weight of solvent =1800-1620 = 180gm

\therefore Molality = \frac{1620}{98}\times \frac{100}{180}=9.18

Relation between concentration terms (Molality & Molarity) -

\dpi{100} m=\frac{1000M}{1000d-Mm_{1}}

- wherein

m=Molality

M=Molarity

m_{1}=Molar\: mass\: of \: solute

\dpi{100} d=density\: of \: solution \: g/ml

 

 The density of solution = 1.8gm/ml
Weight of one litre of solution = 1800gm

 \therefore  Weight of H_{2}SO_{4} in the solution = =\frac{1800\times 90}{100}= 162gm

\therefore Weight of solvent =1800-1620 = 180gm

\therefore Molality = \frac{1620}{98}\times \frac{100}{180}=9.18

Posted by

Varun Chauhan

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