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  • The needle of a deflection galvanometer shows a deflection 60o due to a short bar magnet at a certain distance in  <img alt="tan A" src="https://entrancecorner.oncodecogs.com/g

The needle of a deflection galvanometer shows a deflection 60o due to a short bar magnet at a certain distance in  tan A position. If the distance doubled , the deflection is 

Option: 1

\sin^{-1}\frac{\sqrt{3}}{8}   


Option: 2

cos^{-1}\frac{\sqrt{3}}{8}


Option: 3

tan^{-1}\frac{\sqrt{3}}{8}


Option: 4

cot^{-1}\frac{\sqrt{3}}{8}


Answers (1)

best_answer

For short bar magnet in tan A position

 \frac{uo}{4\pi } \frac{2m}{d^3} = H tan \theta

When distance is doubled, then new deflection \theta'  is given by

\frac{uo}{4\pi } \frac{2m}{ (2d)^3} = H tan \theta'

\therefore \frac{tan \theta' }{tan \theta } =\frac{1 }{8 } 

\Rightarrow tan \theta' =\frac{tan \theta }{8} =  \frac{tan60^{0}}{8}=\frac{\sqrt{3}}{8}

\Rightarrow  '\theta'=tan ^{-1}(\frac{\sqrt{3}}{8})  

Posted by

Divya Prakash Singh

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