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The nessler's reagent is
Option: 1
K₂HgI₄

Option: 2
HgI₂

Option: 3
NH₂-Hg-O-Hg-I

Option: 4
K₂HgI₄+ KOH

Answers (1)

best_answer

As we learnt ,

Ammonia and its salt with nessler's reagent -

Gives brown precipitate due to the formation of Millon's base

- wherein

$K_{2}HgI_{4}\rightleftharpoons 2KI+HgI_{2}$
$HgI_{2}+2NH_{3}\rightarrow I-Hg-NH_{2}+NH_{4}I$
$2NH_{2}-Hg-I+H_{2}O\rightarrow NH_{2}-Hg-O-Hg-I+NH_{4}I$
$2K_{2}HgI_{4}+NH_{3}+3KOH\rightarrow H_{2}N-Hg-O-Hg-I+7KI+2H_{2}O$

Nessler's reagent is the mixture of K₂HgI₄ and KOH.

Therefore, option (4) is correct.

Posted by

Shailly goel

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