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The number of 90^{\circ} angle in IF_5 are

Option: 1

8


Option: 2

5


Option: 3

6


Option: 4

zero


Answers (1)

best_answer

As we have learnt,

The IF_5 molecule is sp3d2 hybridised and has a square pyramidal shape

Due to lone pair bond pair repulsion there is a distortion in the molecule and as a result there is no 90^{\circ} bond angle.

Hence, the correct answer is Option (4)

Posted by

Sanket Gandhi

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