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The peak current in circcuit is 

Option: 1

40mA


Option: 2

4.14mA


Option: 3

10mA


Option: 4

26.31mA


Answers (1)

best_answer

 

V = 20\sin\omega t

i = \frac{V}{R} = \frac{20\sin\omega t}{2\times 10^3} A

I= (10mA)\sin\omega t

Peak Current = 10 mA

 

Posted by

Nehul

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