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  • The plot of   <img alt="\ln \frac{c_{0}}{c_{0}-x} \: \:\: vs\: \: \: t" src="http://entrancecorner.oncodecogs.com/gif.latex?%5Cln%20%5Cfrac%7Bc_%7B0%7D%7D%7Bc_%7B0%7D-x%7D%20%5C%3A

The plot of
  \ln \frac{c_{0}}{c_{0}-x} \: \:\: vs\: \: \: t
is a straight line, showing the reaction to be a:

Option: 1

Zero order reaction


Option: 2

First order reaction


Option: 3

Second order reaction


Option: 4

Half order reaction


Answers (1)

best_answer

\begin{array}{l}{\text { The plot of } \ln \frac{c_{0}}{c_{0}-x} \text { or } \ln \frac{[\mathrm{A}]_{0}}{[\mathrm{A}]_{0}-x} \text { vs } t \text { is a straight line }} \\ {\text { for first order reaction. }}\end{array}

 

First-order reaction equation

\mathrm{kt= \ln \frac{[\mathrm{A}]_{0}}{[\mathrm{A}]_{0}-x} }

It is a form of y = mx straight line.


Therefore, option(2) is correct

Posted by

sudhir.kumar

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