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1550745969258301764173.jpg Sr,,why we are taking rms here

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@Mannika

PE=\frac{1}{2}LI_0^2

steady state current = V/R=I=\frac{\sqrt2 V_m}{R}  ={5}{\sqrt{2} }\ A

PE=\frac{1}{2}5\times 50=125J

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Safeer PP

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Unless otherwise mentioned the given voltage in AC circuit is RMS value. If it is mentioned in the question that the given value 100 volt is peak value the answer would be 62.5

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Safeer PP

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