If n = 2p-1 (2p-1) where (2p-1) is a prime then the sum of the divisors of n is equal to
1547574303600428542361.jpg n = 2p-1 (2p-1)
divisors will be one of the form (2p-1) where p = 1,2,3......
sum of all divisors will be
=1+ SIGMA from p = 1 to p ((2p-1))
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