Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • The time period of oscillation of a freely suspended magnet is 4 s. If it is broken in length into two equal parts and one part is suspended in the same way, its time period will be.<div class=

The time period of oscillation of a freely suspended magnet is 4 s. If it is broken in length into two equal parts and one part is suspended in the same way, its time period will be.

Option: 1

4 s


Option: 2

2 s


Option: 3

0.5 s


Option: 4

0.25 s


Answers (1)

best_answer

\mathrm{ T=2 \pi \sqrt{\frac{I}{M B_H},} ~~~~~~\begin{aligned} & M \rightarrow \frac{M}{2} \rightarrow \frac{1}{2} \text { th } \\ & I \rightarrow \frac{m L^2}{12} \rightarrow \frac{1}{8} \text { th } \end{aligned}}

Posted by

vinayak

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2026 application correction begins on jeemain.nta.nic.in; edit details by December 2
anam-khan

JEE Mains 2026 LIVE: NTA to conduct session 1 from January 21 to 30; exam pattern, syllabus
anam-khan

JEE Main 2026 correction window opens tomorrow; NTA allows exam city change

Latest Question