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The total number of p\pi-d\pi bond in SO_3 is

Option: 1

6


Option: 2

4


Option: 3

3


Option: 4

2


Answers (1)

best_answer

As we learnt

No. of \sigma  bonds = 3 

No. of \pi bonds = 3 

Hybridization = sp^2

Which suggests one of the 3  \pi bonds is made by  p\pi - p\pi  orbitals.

So, no. of orbitals of p\pi - p\pi bonds = 2 

In SO3 , S atom is in its 3rd excited state.

Posted by

Gaurav

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